| 摘要: |
| 证明丢番图方程y(y+1)(y+2)=dx(x+1)(x+2)的所有整数解满足max{︱x︱,︱y︱}<C,其中,d是一个给定整数,C为仅依赖于d的有效常数.特别地,给出当d=2时方程的全部整数解. |
| 关键词: 丢番图方程 整数解 有效常数 |
| DOI： |
| 投稿时间：2007-07-27 |
| 基金项目: |
|
| The Integer Solution on the Diophantine Equation y (y+1) (y+2)=2x (x+1) (x+2) |
|
LI Jin-xiang
|
| (Department of Mathematics, Guangxi University for Nationalities, Nanning, Guangxi, 530006, China) |
| Abstract: |
| Let d be a given integer, all integer solutions of the diophantine equationcan y (y+1) (y+2)=dx (x+1) (x+2)are effective determined, i.e.max {|x|, |y|}<C (effectively computable constant depending only d).In particular, all solutions can be determined when d=2. |
| Key words: Diophantine equation integer solutiion effective constant |
